16k^2+132k+156=0

Solution for 16k^2+132k+156=0 equation:

16k^2+132k+156=0

a = 16; b = 132; c = +156;
Δ = b2-4ac
Δ = 1322-4·16·156
Δ = 7440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7440}=\sqrt{16*465}=\sqrt{16}*\sqrt{465}=4\sqrt{465}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(132)-4\sqrt{465}}{2*16}=\frac{-132-4\sqrt{465}}{32}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(132)+4\sqrt{465}}{2*16}=\frac{-132+4\sqrt{465}}{32}
$